The equivalent weight of H_2O_2 is: | vedclass

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Question

(A) The equivalent weight of a substance is calculated as the molar mass divided by the $n$-factor.For $H_2O_2$,the molar mass is $2 	imes 1 + 2 	im

Vedclass · Accepted Answer

$17$

Vedclass · Answer

(A) The equivalent weight of a substance is calculated as the molar mass divided by the $n$-factor.For $H_2O_2$,the molar mass is $2 	imes 1 + 2 	imes 16 = 34 \ g/mol$.In redox reactions,$H_2O_2$ acts as an oxidizing or reducing agent,typically involving a change in oxidation state of oxygen from $-1$ to $-2$ or $0$,resulting in an $n$-factor of $2$.Therefore,the equivalent weight = $\frac{	ext{Molar mass}}{n	ext{-factor}} = \frac{34}{2} = 17$.

The equivalent weight of $H_2O_2$ is:

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