Evaluate frac{0.53 times 0.53 - 2 times 0.53 | vedclass

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Question

(C) The given expression is in the form $\frac{a^2 - 2ab + b^2}{a - b}$,where $a = 0.53$ and $b = 0.41$.Using the algebraic identity $a^2 - 2ab + b^2

Vedclass · Accepted Answer

$0.12$

Vedclass · Answer

(C) The given expression is in the form $\frac{a^2 - 2ab + b^2}{a - b}$,where $a = 0.53$ and $b = 0.41$.Using the algebraic identity $a^2 - 2ab + b^2 = (a - b)^2$,the numerator becomes $(0.53 - 0.41)^2$.Substituting the values,we get $\frac{(0.53 - 0.41)^2}{0.53 - 0.41}$.This simplifies to $(0.53 - 0.41) = 0.12$.Therefore,the correct answer is $0.12$.

Evaluate $\frac{0.53 \times 0.53 - 2 \times 0.53 \times 0.41 + 0.41 \times 0.41}{0.53 - 0.41}$

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