(B) The given expression is in the form of $(a + b)(a - b)$,where $a = \frac{2x}{3}$ and $b = \frac{4y}{5}$.Using the algebraic identity $(a + b)(a -

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$\frac{4}{9}x^2 - \frac{16}{25}y^2$

(B) The given expression is in the form of $(a + b)(a - b)$,where $a = \frac{2x}{3}$ and $b = \frac{4y}{5}$.Using the algebraic identity $(a + b)(a - b) = a^2 - b^2$,we get:$\left(\frac{2x}{3}\right)^2 - \left(\frac{4y}{5}\right)^2$$= \frac{4x^2}{9} - \frac{16y^2}{25}$$= \frac{4}{9}x^2 - \frac{16}{25}y^2$.