Expected children of a blue-eyed (recessive) | vedclass

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(B) Let the allele for brown eyes be $B$ (dominant) and blue eyes be $b$ (recessive).$1$. The woman is blue-eyed, so her genotype must be $bb$.$2$. Th

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One blue-eyed and one brown-eyed

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(B) Let the allele for brown eyes be $B$ (dominant) and blue eyes be $b$ (recessive).$1$. The woman is blue-eyed, so her genotype must be $bb$.$2$. The man is brown-eyed, so he must have at least one $B$ allele. Since his mother was blue-eyed $(bb)$, he must have inherited one $b$ allele from her. Therefore, his genotype is $Bb$.$3$. The cross is $bb$ (woman) $	imes$ $Bb$ (man).$4$. The possible offspring genotypes are $Bb$ (brown-eyed) and $bb$ (blue-eyed) in a $1:1$ ratio.$5$. Thus, $50\%$ of the children are expected to be brown-eyed and $50\%$ are expected to be blue-eyed.

$S.No$	Cross	Result
$I.$ Strain $1 \times gg$	All wild type
$II.$ Strain $2 \times gg$	$1$ wild type $: 1$ ebony
$III.$ Strain $3 \times gg$	All ebony
$IV.$ Strain $4 \times Gg$	$3$ wild type $: 1$ ebony

Expected children of a blue-eyed (recessive) woman and brown-eyed (dominant) man who had a blue-eyed mother are likely to be:

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