Explain why elemental semiconductors cannot be used to make visible $LEDs$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The band gap energy of elemental semiconductors, such as silicon $(Si)$ or germanium $(Ge)$, is relatively small. For silicon, the band gap is approximately $1.1 \text{ eV}$, and for germanium, it is about $0.67 \text{ eV}$.
Visible light corresponds to photon energies ranging from approximately $1.8 \text{ eV}$ to $3.1 \text{ eV}$.
Since the band gap of elemental semiconductors is too small, the energy released during electron-hole recombination is insufficient to produce photons in the visible spectrum. Instead, they emit radiation in the infrared region.
Therefore, compound semiconductors with larger band gaps are required to produce visible light $LEDs$.

Explore More

Similar Questions

Which wavelength of the Sun is primarily used to generate electric energy in solar cells?

Three photodiodes $D_{1}, D_{2}$ and $D_{3}$ are made of semiconductors having band gaps of $2.5 eV, 2 eV$ and $3 eV$,respectively. Which one will be able to detect light of wavelength $600 nm$?

Which of the following semiconductor devices requires a reverse bias to operate?

The symbolic representation of a photodiode is:

The material suitable for making a solar cell is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo