Explain why propanol has a higher boiling point than that of the hydrocarbon,butane?
(N/A) Propanol $(CH_3CH_2CH_2OH)$ undergoes intermolecular hydrogen bonding due to the presence of the polar $-OH$ group.
On the other hand,butane $(C_4H_{10})$ is a non-polar hydrocarbon and only exhibits weak van der Waals forces.
Because of the strong intermolecular hydrogen bonds in propanol,extra energy is required to overcome these forces during the phase transition.
Therefore,propanol has a significantly higher boiling point than butane.
On the other hand,butane $(C_4H_{10})$ is a non-polar hydrocarbon and only exhibits weak van der Waals forces.
Because of the strong intermolecular hydrogen bonds in propanol,extra energy is required to overcome these forces during the phase transition.
Therefore,propanol has a significantly higher boiling point than butane.
Explore More
Similar Questions
Ethanol,when reacted with $PCl_5$,gives $A$,$POCl_3$,and $HCl$. $A$ reacts with silver nitrite $(AgNO_2)$ to form $B$ (major product) and $AgCl$. $A$ and $B$ are respectively:
The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with
MediumKCET 2009
View SolutionThe major product of the following reaction is $:-$
$CH_3-CH(CH_3)-CH(OH)-CH_3 \xrightarrow{HBr} \text{Major Product}$
$CH_3-CH(CH_3)-CH(OH)-CH_3 \xrightarrow{HBr} \text{Major Product}$
Medium
View SolutionWhich reagent is required to convert cyclohexanol to cyclohexanone?
The order of reactivity of the following compounds towards the esterification with acetic acid is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo