Express $\cot 85^{\circ}+\cos 75^{\circ}$ in terms of trigonometric ratios of angles between $0^{\circ}$ and $45^{\circ}$.

(N/A) To express the given expression in terms of angles between $0^{\circ}$ and $45^{\circ}$,we use the complementary angle identities: $\cot(90^{\circ}-\theta) = \tan \theta$ and $\cos(90^{\circ}-\theta) = \sin \theta$.
Given expression: $\cot 85^{\circ} + \cos 75^{\circ}$
Step $1$: Rewrite $85^{\circ}$ as $(90^{\circ}-5^{\circ})$ and $75^{\circ}$ as $(90^{\circ}-15^{\circ})$.
$\cot(90^{\circ}-5^{\circ}) + \cos(90^{\circ}-15^{\circ})$
Step $2$: Apply the identities.
$= \tan 5^{\circ} + \sin 15^{\circ}$
Since $5^{\circ}$ and $15^{\circ}$ are both between $0^{\circ}$ and $45^{\circ}$,the expression is now in the required form.