Factorise: $49x^2 - 121$

Verify whether the following are True or False:
$0$ and $2$ are the zeroes of $t^{2}-2t$.

If $a+b+c=9$ and $ab+bc+ca=26$,find $a^{2}+b^{2}+c^{2}$.

Find the value of $m$ so that $2x - 1$ is a factor of $8x^4 + 4x^3 - 16x^2 + 10x + m$.

Expand $(2x + 3y + 5)^2$.

Without actually calculating the cubes,find the value of each of the following:
$\left(\frac{1}{2}\right)^{3}+\left(\frac{1}{3}\right)^{3}-\left(\frac{5}{6}\right)^{3}$