Factorise the following:
$9 x^{2}-12 x+3$

(N/A) To factorise the quadratic expression $9 x^{2}-12 x+3$,we use the splitting the middle term method.
First,we find two numbers whose product is $9 \times 3 = 27$ and whose sum is $-12$.
These two numbers are $-9$ and $-3$.
Now,rewrite the middle term $-12 x$ as $-9 x - 3 x$:
$9 x^{2}-9 x-3 x+3$
Group the terms:
$=9 x(x-1)-3(x-1)$
Factor out the common binomial $(x-1)$:
$=(9 x-3)(x-1)$
Finally,factor out the common constant $3$ from the first binomial:
$=3(3 x-1)(x-1)$