Ferrous ion changes to X ion upon reacting wi | vedclass

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(B) The reaction of ferrous ion $(Fe^{2+})$ with acidified hydrogen peroxide $(H_2O_2)$ results in the oxidation of $Fe^{2+}$ to ferric ion $(Fe^{3+})

Vedclass · Accepted Answer

$5$ and $5.92$

Vedclass · Answer

(B) The reaction of ferrous ion $(Fe^{2+})$ with acidified hydrogen peroxide $(H_2O_2)$ results in the oxidation of $Fe^{2+}$ to ferric ion $(Fe^{3+})$: $2Fe^{2+} + H_2O_2 + 2H^+ \longrightarrow 2Fe^{3+} + 2H_2O$ Thus,the ion $X$ is $Fe^{3+}$. The electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$. The number of $d$-electrons is $5$. The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. For $Fe^{3+}$,$n = 5$. $\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \ BM$.

Ferrous ion changes to $X$ ion upon reacting with acidified hydrogen peroxide. The number of $d$-electrons present in $X$ and its magnetic moment (in $BM$) are,respectively:

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