Figure (i) below shows a Wheatstone's bridge | vedclass

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(C) In case $(i)$,the galvanometer shows zero deflection,which implies the bridge is balanced.Therefore,the condition for a balanced Wheatstone bridge

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is zero

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(C) In case $(i)$,the galvanometer shows zero deflection,which implies the bridge is balanced.Therefore,the condition for a balanced Wheatstone bridge is given by $\frac{P}{S} = \frac{Q}{R}$,which can be rewritten as $\frac{P}{Q} = \frac{S}{R}$.When the battery $B$ and galvanometer $G$ are interchanged as shown in figure $(ii)$,the new condition for the galvanometer to show zero deflection is that the ratio of resistances in the arms connected to the galvanometer must be equal.In the new configuration,the ratio of resistances is $\frac{P}{Q}$ and $\frac{S}{R}$.Since we already established from the balanced condition in case $(i)$ that $\frac{P}{Q} = \frac{S}{R}$,the bridge remains balanced in the new configuration.Hence,the galvanometer still shows zero deflection.

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