The figure shows the circular motion of a particle. The radius of the circle is $B$. The particle starts at $t=0$ from the positive $y$-axis and moves clockwise. The simple harmonic motion of the $x$-projection of the radius vector of the rotating particle is given by:

• A
  $x(t) = B \sin \left( \frac{2\pi t}{T} + \frac{\pi}{2} \right)$
• B
  $x(t) = B \cos \left( \frac{2\pi t}{T} \right)$
• C
  $x(t) = B \sin \left( \frac{2\pi t}{T} \right)$
• D
  $x(t) = B \cos \left( \frac{2\pi t}{T} + \frac{\pi}{2} \right)$