The figure shows the energy levels P, Q, R, S | vedclass

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(D) The energy of a photon emitted during a transition is given by $E = h
u = \frac{hc}{\lambda}$.Since the wavelength of blue light is shorter than

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$R$ to $G$

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(D) The energy of a photon emitted during a transition is given by $E = h
u = \frac{hc}{\lambda}$.Since the wavelength of blue light is shorter than that of red light $(\lambda_{	ext{blue}}  E_{	ext{red}})$.Given that the transition from $Q$ to $S$ corresponds to a red line,we need a transition with a larger energy difference than $E_{Q 	o S}$.Looking at the energy level diagram,the transition from $R$ to $G$ involves a larger energy gap compared to $Q$ to $S$.Therefore,the transition $R$ to $G$ will emit a photon with higher energy,corresponding to the blue line.Thus,option $(d)$ is correct.

The figure shows the energy levels $P, Q, R, S$ and $G$ of an atom,where $G$ is the ground state. $A$ red line in the emission spectrum of the atom is obtained by an energy level transition from $Q$ to $S$. $A$ blue line can be obtained by which of the following energy level transitions?

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