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(C) The given series is $3, 9, 15, . . .$Here,the difference between consecutive terms is constant: $9 - 3 = 6$ and $15 - 9 = 6$.Thus,this is an Arith

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$123$

Vedclass · Answer

(C) The given series is $3, 9, 15, . . .$Here,the difference between consecutive terms is constant: $9 - 3 = 6$ and $15 - 9 = 6$.Thus,this is an Arithmetic Progression $(A.P.)$ where the first term $a = 3$ and the common difference $d = 6$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.For the $21^{st}$ term $(n = 21)$:$a_{21} = 3 + (21 - 1) 	imes 6$$a_{21} = 3 + 20 	imes 6$$a_{21} = 3 + 120 = 123$.

Fill in the blank space for the given series with the correct alternative.
In the series $3, 9, 15, . . .$ what will be the $21^{st}$ term?

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Fill in the blank space for the given series with the correct alternative.In the series $3, 9, 15, . . .$ what will be the $21^{st}$ term?