Find AB, if A = begin{bmatrix} 0 & -1 0 & 2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given $A = \begin{bmatrix} 0 & -1 \ 0 & 2 \end{bmatrix}$ and $B = \begin{bmatrix} 3 & 5 \ 0 & 0 \end{bmatrix}$.To find $AB$,we perform matrix mu

Vedclass · Accepted Answer

$\begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix}$

Vedclass · Answer

(A) Given $A = \begin{bmatrix} 0 & -1 \ 0 & 2 \end{bmatrix}$ and $B = \begin{bmatrix} 3 & 5 \ 0 & 0 \end{bmatrix}$.To find $AB$,we perform matrix multiplication:$AB = \begin{bmatrix} 0 & -1 \ 0 & 2 \end{bmatrix} \begin{bmatrix} 3 & 5 \ 0 & 0 \end{bmatrix}$$AB = \begin{bmatrix} (0 	imes 3) + (-1 	imes 0) & (0 	imes 5) + (-1 	imes 0) \ (0 	imes 3) + (2 	imes 0) & (0 	imes 5) + (2 	imes 0) \end{bmatrix}$$AB = \begin{bmatrix} 0 + 0 & 0 + 0 \ 0 + 0 & 0 + 0 \end{bmatrix} = \begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix}$.Thus,the product $AB$ is the zero matrix $\begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix}$.

Find $AB,$ if $A = \begin{bmatrix} 0 & -1 \\ 0 & 2 \end{bmatrix}$ and $B = \begin{bmatrix} 3 & 5 \\ 0 & 0 \end{bmatrix}$.

Similar Questions

If $x \begin{bmatrix} 2 \\ 3 \end{bmatrix} + y \begin{bmatrix} -1 \\ 1 \end{bmatrix} = \begin{bmatrix} 10 \\ 5 \end{bmatrix}$,find the values of $x$ and $y$.

Let $G(x) = \begin{bmatrix} \cos x & -\sin x & 0 \\ \sin x & \cos x & 0 \\ 0 & 0 & 1 \end{bmatrix}$. If $x+y=0$,then $G(x) G(y) =$

If $A$ is a nilpotent matrix of index $2$,then $A(I_2+A)^{51}$ is equal to (where $I_2$ is the identity matrix of order $2$)

The characteristic roots of the matrix $\left[\begin{array}{ccc}1 & 0 & 0 \\ 2 & 3 & 0 \\ 4 & 5 & 6\end{array}\right]$ are

If $\begin{bmatrix} 2 & 3 & 4 \end{bmatrix} \begin{bmatrix} 1 & x & 3 \\ 2 & 4 & 5 \\ 3 & 2 & x \end{bmatrix} \begin{bmatrix} x \\ 2 \\ 0 \end{bmatrix} = O$,then $x = $ . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module