Find X, if Y = begin{bmatrix} 3 & 2 1 & 4 en | vedclass

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(A) Given the equation $2X + Y = \begin{bmatrix} 1 & 0 \ -3 & 2 \end{bmatrix}$ and $Y = \begin{bmatrix} 3 & 2 \ 1 & 4 \end{bmatrix}$.Substitute the

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$\begin{bmatrix} -1 & -1 \ -2 & -1 \end{bmatrix}$

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(A) Given the equation $2X + Y = \begin{bmatrix} 1 & 0 \ -3 & 2 \end{bmatrix}$ and $Y = \begin{bmatrix} 3 & 2 \ 1 & 4 \end{bmatrix}$.Substitute the matrix $Y$ into the equation:$2X + \begin{bmatrix} 3 & 2 \ 1 & 4 \end{bmatrix} = \begin{bmatrix} 1 & 0 \ -3 & 2 \end{bmatrix}$Subtract matrix $Y$ from both sides:$2X = \begin{bmatrix} 1 & 0 \ -3 & 2 \end{bmatrix} - \begin{bmatrix} 3 & 2 \ 1 & 4 \end{bmatrix}$$2X = \begin{bmatrix} 1-3 & 0-2 \ -3-1 & 2-4 \end{bmatrix}$$2X = \begin{bmatrix} -2 & -2 \ -4 & -2 \end{bmatrix}$Divide by $2$ to find $X$:$X = \frac{1}{2} \begin{bmatrix} -2 & -2 \ -4 & -2 \end{bmatrix} = \begin{bmatrix} -1 & -1 \ -2 & -1 \end{bmatrix}$

Find $X,$ if $Y = \begin{bmatrix} 3 & 2 \\ 1 & 4 \end{bmatrix}$ and $2X + Y = \begin{bmatrix} 1 & 0 \\ -3 & 2 \end{bmatrix}$.

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