Find $p(0)$,$p(1)$,and $p(2)$ for the following polynomial: $p(y) = y^{2} - y + 1$.

(N/A) Given polynomial: $p(y) = y^{2} - y + 1$.
To find $p(0)$,substitute $y = 0$ into the polynomial:
$p(0) = (0)^{2} - (0) + 1 = 0 - 0 + 1 = 1$.
To find $p(1)$,substitute $y = 1$ into the polynomial:
$p(1) = (1)^{2} - (1) + 1 = 1 - 1 + 1 = 1$.
To find $p(2)$,substitute $y = 2$ into the polynomial:
$p(2) = (2)^{2} - (2) + 1 = 4 - 2 + 1 = 3$.