Find $p(0)$,$p(1)$,and $p(2)$ for the following polynomial: $p(x) = (x - 1)(x + 1)$.
(N/A) Given the polynomial $p(x) = (x - 1)(x + 1)$.
To find $p(0)$,substitute $x = 0$ into the polynomial:
$p(0) = (0 - 1)(0 + 1) = (-1)(1) = -1$.
To find $p(1)$,substitute $x = 1$ into the polynomial:
$p(1) = (1 - 1)(1 + 1) = (0)(2) = 0$.
To find $p(2)$,substitute $x = 2$ into the polynomial:
$p(2) = (2 - 1)(2 + 1) = (1)(3) = 3$.
To find $p(0)$,substitute $x = 0$ into the polynomial:
$p(0) = (0 - 1)(0 + 1) = (-1)(1) = -1$.
To find $p(1)$,substitute $x = 1$ into the polynomial:
$p(1) = (1 - 1)(1 + 1) = (0)(2) = 0$.
To find $p(2)$,substitute $x = 2$ into the polynomial:
$p(2) = (2 - 1)(2 + 1) = (1)(3) = 3$.
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