Find A,B and C in the following reactions:NH_ | vedclass

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(D) The given reactions are part of the Solvay process for the production of sodium carbonate.$1$. $2NH_3 + H_2O(A) + CO_2 \rightarrow (NH_4)_2CO_3$$2

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$A - H_2O; B - CO_2; C - NaHCO_3$

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(D) The given reactions are part of the Solvay process for the production of sodium carbonate.$1$. $2NH_3 + H_2O(A) + CO_2 \rightarrow (NH_4)_2CO_3$$2$. $(NH_4)_2CO_3 + H_2O + CO_2(B) \rightarrow 2NH_4HCO_3$$3$. $NH_4HCO_3 + NaCl \rightarrow NaHCO_3(C) + NH_4Cl$Comparing these with the given equations,we identify $A = H_2O$,$B = CO_2$,and $C = NaHCO_3$.

Find $A$,$B$ and $C$ in the following reactions:
$NH_3 + A + CO_2 \rightarrow (NH_4)_2CO_3$
$(NH_4)_2CO_3 + H_2O + B \rightarrow 2NH_4HCO_3$
$NH_4HCO_3 + NaCl \rightarrow NH_4Cl + C$

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Find $A$,$B$ and $C$ in the following reactions:$NH_3 + A + CO_2 \rightarrow (NH_4)_2CO_3$$(NH_4)_2CO_3 + H_2O + B \rightarrow 2NH_4HCO_3$$NH_4HCO_3 + NaCl \rightarrow NH_4Cl + C$