Find the value of V_{AB} in the given circuit | vedclass

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(A) The diode is in forward bias, so it acts as a short circuit (assuming an ideal diode). The circuit can be redrawn by replacing the diode with a wi

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$10 \, V$

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(A) The diode is in forward bias, so it acts as a short circuit (assuming an ideal diode). The circuit can be redrawn by replacing the diode with a wire. The $10 \, \Omega$ resistor in the middle and the $10 \, \Omega$ resistor in the branch with the diode are now in parallel. The equivalent resistance of these two parallel resistors is $R_p = \frac{10 	imes 10}{10 + 10} = 5 \, \Omega$. Now, the circuit consists of a $30 \, V$ source in series with a $10 \, \Omega$ resistor and the equivalent $5 \, \Omega$ resistor. The voltage $V_{AB}$ across the parallel combination is given by the voltage divider rule: $V_{AB} = \frac{R_p}{R_1 + R_p} 	imes V_{total} = \frac{5}{10 + 5} 	imes 30 = \frac{5}{15} 	imes 30 = 10 \, V$.

Find the value of $V_{AB}$ in the given circuit.

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