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(D) Given,the perimeter of the circular base (circumference) is $2\pi r = 8.8\, m$.The curved surface area of the cylindrical pillar is $2\pi rh = 17.

Vedclass · Accepted Answer

$12 \frac{8}{25}\, m^3$

Vedclass · Answer

(D) Given,the perimeter of the circular base (circumference) is $2\pi r = 8.8\, m$.The curved surface area of the cylindrical pillar is $2\pi rh = 17.6\, m^2$.Dividing the curved surface area by the circumference: $\frac{2\pi rh}{2\pi r} = \frac{17.6}{8.8} = 2$. Thus,the height $h = 2\, m$.Using $2\pi r = 8.8$,we have $2 	imes \frac{22}{7} 	imes r = 8.8$,which gives $r = \frac{8.8 	imes 7}{44} = 0.2 	imes 7 = 1.4\, m$.The amount of concrete required is equal to the volume of the cylinder,$V = \pi r^2 h$.$V = \frac{22}{7} 	imes (1.4)^2 	imes 2 = \frac{22}{7} 	imes 1.96 	imes 2 = 22 	imes 0.28 	imes 2 = 12.32\, m^3$.Converting $12.32$ to a fraction: $12.32 = 12 + \frac{32}{100} = 12 + \frac{8}{25} = 12 \frac{8}{25}\, m^3$.

Find out the amount of concrete required to erect a concrete pillar whose circular base has a perimeter of $8.8\, m$ and whose curved surface area is $17.6\, m^2$. $\left(\pi=\frac{22}{7}\right)$

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