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(A) The reaction involves the formation of a Grignard reagent from an allyl bromide followed by a Wurtz-type coupling reaction.$1$. $CH_2=CH-CH_2Br +

Vedclass · Accepted Answer

$CH_2=CH-CH_2-CH_2-CH=CH_2$

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(A) The reaction involves the formation of a Grignard reagent from an allyl bromide followed by a Wurtz-type coupling reaction.$1$. $CH_2=CH-CH_2Br + Mg \xrightarrow{T.H.F.} CH_2=CH-CH_2MgBr$ (Allylmagnesium bromide).$2$. The Grignard reagent reacts with another molecule of allyl bromide: $CH_2=CH-CH_2MgBr + CH_2=CH-CH_2Br \rightarrow CH_2=CH-CH_2-CH_2-CH=CH_2 + MgBr_2$.This is a coupling reaction resulting in the formation of $1,5-hexadiene$.

Find out the major product of the following reaction:
$2 \text{ mole } CH_2=CH-CH_2Br \xrightarrow{Mg, T.H.F.} \text{?}$

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Find out the major product of the following reaction:$2 \text{ mole } CH_2=CH-CH_2Br \xrightarrow{Mg, T.H.F.} \text{?}$