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(C) The chemical formula of glucose is $C_6H_{12}O_6$. One mole of glucose contains $6 \ mol$ of carbon atoms. Therefore,$0.35 \ mol$ of glucose conta

Vedclass · Accepted Answer

$1.264 	imes 10^{24}$

Vedclass · Answer

(C) The chemical formula of glucose is $C_6H_{12}O_6$. One mole of glucose contains $6 \ mol$ of carbon atoms. Therefore,$0.35 \ mol$ of glucose contains $0.35 	imes 6 = 2.1 \ mol$ of carbon atoms. The number of carbon atoms is calculated as $2.1 	imes N_A$,where $N_A = 6.022 	imes 10^{23} \ mol^{-1}$. Number of carbon atoms $= 2.1 	imes 6.022 	imes 10^{23} = 12.6462 	imes 10^{23} = 1.26462 	imes 10^{24}$. Thus,the correct option is $C$.

Find out the number of carbon atoms present in $0.35 \ mol$ of glucose.

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