Find the potential difference between A and B | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the steady state,the capacitors act as open circuits,meaning no current flows through the branches containing capacitors. Since there is no cur

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(D) In the steady state,the capacitors act as open circuits,meaning no current flows through the branches containing capacitors. Since there is no current flowing in the circuit $(I = 0)$,there is no voltage drop across the resistors ($200 \ \Omega$ and $10 \ \Omega$). Therefore,the entire potential difference of the battery $(100 \ V)$ appears across the parallel branches connected to the battery terminals. Let the potential of the bottom wire be $0 \ V$. Then the potential of the top wire is $100 \ V$. The branch containing $A$ and $B$ is connected in parallel to the battery. Since no current flows,the potential at point $A$ is the same as the potential of the left terminal of the battery,and the potential at point $B$ is the same as the potential of the right terminal of the battery. Thus,the potential difference $V_{AB} = V_A - V_B = 100 \ V$.

Find the potential difference between $A$ and $B$ in the given circuit in the steady state. (in $V$)

Similar Questions

The values of charges $q_1, q_2$ and $q_3$ as shown in the figure are:

The resultant capacitance between $A$ and $B$ in the figure is ...... $\mu F$.

In the circuit shown,$q_2$ and $q_3$ are respectively (Initially all capacitors are uncharged).

When a parallel plate capacitor is connected to a source of constant potential difference,

Vedclass Test Series

Exam Paper Generator

Online Exam Module