Find the HCF(510, 92). | vedclass

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Question

(B) To find the $HCF(510, 92)$,we perform prime factorization of both numbers:$510 = 2 	imes 3 	imes 5 	imes 17$$92 = 2 	imes 2 	imes 23 = 2^2

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) To find the $HCF(510, 92)$,we perform prime factorization of both numbers:$510 = 2 	imes 3 	imes 5 	imes 17$$92 = 2 	imes 2 	imes 23 = 2^2 	imes 23$The $HCF$ is the product of the smallest power of each common prime factor.The only common prime factor is $2$,and its smallest power is $2^1 = 2$.Therefore,$HCF(510, 92) = 2$.

Find the $HCF(510, 92)$.

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