Find the HCF and LCM of the following pairs o | vedclass

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(A) Step $1$: Prime factorization of $26$ and $91$.$26 = 2 	imes 13$$91 = 7 	imes 13$Step $2$: Find $HCF$ and $LCM$.$HCF = 	ext{Product of the smal

Vedclass · Accepted Answer

$HCF = 13, LCM = 182; 2366 = 2366$

Vedclass · Answer

(A) Step $1$: Prime factorization of $26$ and $91$.$26 = 2 	imes 13$$91 = 7 	imes 13$Step $2$: Find $HCF$ and $LCM$.$HCF = 	ext{Product of the smallest power of each common prime factor} = 13$.$LCM = 	ext{Product of the greatest power of each prime factor involved} = 2 	imes 7 	imes 13 = 182$.Step $3$: Verify the relationship $HCF 	imes LCM = 	ext{Product of the two numbers}$.$HCF 	imes LCM = 13 	imes 182 = 2366$.$	ext{Product of the two numbers} = 26 	imes 91 = 2366$.Since $2366 = 2366$, the relationship is verified.

Find the $HCF$ and $LCM$ of the following pairs of integers and verify that $HCF \times LCM = \text{product of the two numbers}: 26$ and $91$.

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