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(A) To find the area of a triangle with sides $a = 9 \, cm$,$b = 10 \, cm$,and $c = 17 \, cm$,we use Heron's formula.First,calculate the semi-perimete

Vedclass · Accepted Answer

$36$

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(A) To find the area of a triangle with sides $a = 9 \, cm$,$b = 10 \, cm$,and $c = 17 \, cm$,we use Heron's formula.First,calculate the semi-perimeter $s$:$s = \frac{a + b + c}{2} = \frac{9 + 10 + 17}{2} = \frac{36}{2} = 18 \, cm$.Now,use the area formula $	ext{Area} = \sqrt{s(s - a)(s - b)(s - c)}$:$	ext{Area} = \sqrt{18(18 - 9)(18 - 10)(18 - 17)}$$	ext{Area} = \sqrt{18 	imes 9 	imes 8 	imes 1}$$	ext{Area} = \sqrt{1296} = 36 \, cm^2$.

Find the area of the triangle with the length of the sides $9 \, cm$,$10 \, cm$,and $17 \, cm$. (in $, cm^2$)

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