Find the circumference and the area of a circular ground with radius $77\, m$.
(N/A) Given,the radius of the circular ground is $r = 77\, m$.
Circumference of a circle is given by the formula $C = 2\pi r$.
Substituting the values,we get $C = 2 \times \frac{22}{7} \times 77 = 2 \times 22 \times 11 = 484\, m$.
Area of a circle is given by the formula $A = \pi r^2$.
Substituting the values,we get $A = \frac{22}{7} \times 77 \times 77 = 22 \times 11 \times 77 = 18634\, m^2$.
Thus,the circumference of the circular ground is $484\, m$ and the area is $18634\, m^2$.
Circumference of a circle is given by the formula $C = 2\pi r$.
Substituting the values,we get $C = 2 \times \frac{22}{7} \times 77 = 2 \times 22 \times 11 = 484\, m$.
Area of a circle is given by the formula $A = \pi r^2$.
Substituting the values,we get $A = \frac{22}{7} \times 77 \times 77 = 22 \times 11 \times 77 = 18634\, m^2$.
Thus,the circumference of the circular ground is $484\, m$ and the area is $18634\, m^2$.
Explore More
Similar Questions
The circumference of a circle is $88 \, cm$. The length of each side of a square inscribed in that circle is $\ldots \ldots \ldots \, cm$.
Medium
View SolutionAs shown in the diagram,the side length of square garden $ABCD$ is $60\, m$. Flower beds are prepared in the shape of circular segments on two opposite sides of the square. The centre of the circles for these segments is the point of intersection $O$ of the diagonals of square $ABCD$. Find the total area of the two flower beds. (Use $\pi=3.14$) (in $m^2$)
Difficult
View SolutionThe area of a minor sector of $\odot(P, 30)$ is $300 \, cm^2$. The length of the arc corresponding to it is .......... $cm$.
Medium
View SolutionIf the sum of the circumferences of two circles with radii $R_{1}$ and $R_{2}$ is equal to the circumference of a circle of radius $R$,then
Easy
View SolutionAs shown in the diagram,the side length of square $ABCD$ is $21 \ cm$. $\widehat{APC}$ is an arc of $\odot(B, BA)$ and $\widehat{AQC}$ is an arc of $\odot(D, DA)$. Find the area of the shaded portion. (in $cm^2$)
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo