Find the coordinates of the point which divid | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the points be $A(x_1, y_1) = (3, 2)$ and $B(x_2, y_2) = (-2, -5)$.Let the point $P(x, y)$ divide the segment $\overline{AB}$ in the ratio $m:n

Vedclass · Accepted Answer

$\left(0, -2.2\right)$

Vedclass · Answer

(C) Let the points be $A(x_1, y_1) = (3, 2)$ and $B(x_2, y_2) = (-2, -5)$.Let the point $P(x, y)$ divide the segment $\overline{AB}$ in the ratio $m:n = 3:2$ starting from $A$.Using the section formula,the coordinates of $P$ are given by:$x = \frac{mx_2 + nx_1}{m+n} = \frac{3(-2) + 2(3)}{3+2} = \frac{-6 + 6}{5} = \frac{0}{5} = 0$$y = \frac{my_2 + ny_1}{m+n} = \frac{3(-5) + 2(2)}{3+2} = \frac{-15 + 4}{5} = \frac{-11}{5} = -2.2$Thus,the coordinates of the point are $(0, -2.2)$.

Find the coordinates of the point which divides $\overline{AB}$ in the ratio $3:2$ from $A$. The coordinates of $A$ and $B$ are $(3, 2)$ and $(-2, -5)$ respectively.

Similar Questions

The coordinates of the midpoint of the line segment joining the points $(20, 10)$ and $(6, 8)$ are:

Find the circumcentre and the area of the triangle with vertices $(7,9), (10,8)$ and $(12,10)$.

If two of the vertices of an equilateral triangle are $(0,0)$ and $(3, \sqrt{3}),$ find the coordinates of the third vertex.

If $A(0, y_{1})$ and $B(0, y_{2})$ are the points on the $Y$-axis,then the distance between them $AB = \ldots$

The line segment joining $A(-3, 5)$ and $B(2, 5)$ intersects............

Vedclass Test Series

Exam Paper Generator

Online Exam Module