Find the current through the 1,Omega resistan | vedclass

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(A) In the given circuit,there are two diodes in parallel branches. Looking at the orientation of the diodes,the top diode is forward-biased,while the

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$2\,A$

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(A) In the given circuit,there are two diodes in parallel branches. Looking at the orientation of the diodes,the top diode is forward-biased,while the middle diode is reverse-biased. $A$ reverse-biased diode acts as an open circuit,so no current flows through the middle branch. The top branch contains a diode in series with a $2\,\Omega$ resistor. The bottom branch contains a $6\,V$ battery in series with a $1\,\Omega$ resistor. Since the middle branch is open,the circuit simplifies to a series circuit consisting of the $6\,V$ battery,the $1\,\Omega$ resistor,the top diode,and the $2\,\Omega$ resistor. The total resistance of the circuit is $R_{eq} = 1\,\Omega + 2\,\Omega = 3\,\Omega$. The current $I$ in the circuit is given by Ohm's law: $I = \frac{V}{R_{eq}} = \frac{6\,V}{3\,\Omega} = 2\,A$. Thus,the current through the $1\,\Omega$ resistance is $2\,A$.

Find the current through the $1\,\Omega$ resistance in the given circuit.

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