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(A) We know that $\pi 	ext{ radians} = 180^{\circ}$.$-4 	ext{ radians} = \frac{180}{\pi} 	imes (-4) 	ext{ degrees}$.Using $\pi = \frac{22}{7}$,we

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$-229^{\circ} 5^{\prime} 27^{\prime \prime}$

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(A) We know that $\pi 	ext{ radians} = 180^{\circ}$.$-4 	ext{ radians} = \frac{180}{\pi} 	imes (-4) 	ext{ degrees}$.Using $\pi = \frac{22}{7}$,we get:$= \frac{180 	imes 7 	imes (-4)}{22} 	ext{ degrees} = \frac{-2520}{11} 	ext{ degrees} = -229 \frac{1}{11} 	ext{ degrees}$.$= -229^{\circ} + \left( \frac{1}{11} 	imes 60 ight) 	ext{ minutes} \quad [\because 1^{\circ} = 60^{\prime}]$.$= -229^{\circ} + 5 \frac{5}{11} 	ext{ minutes} = -229^{\circ} 5^{\prime} + \left( \frac{5}{11} 	imes 60 ight) 	ext{ seconds} \quad [\because 1^{\prime} = 60^{\prime \prime}]$.$= -229^{\circ} 5^{\prime} + 27.27^{\prime \prime} \approx -229^{\circ} 5^{\prime} 27^{\prime \prime}$.

Find the degree measure corresponding to the following radian measure (Use $\pi = \frac{22}{7}$):
$-4$ radians

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Find the degree measure corresponding to the following radian measure (Use $\pi = \frac{22}{7}$):$-4$ radians