Find the derivative of the following function: $\frac{a}{x^{4}}-\frac{b}{x^{2}}+\cos x$,where $a$ and $b$ are fixed non-zero constants.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Let $f(x) = \frac{a}{x^{4}} - \frac{b}{x^{2}} + \cos x$.
Using the power rule $\frac{d}{dx}(x^n) = nx^{n-1}$ and the derivative of trigonometric functions $\frac{d}{dx}(\cos x) = -\sin x$:
$f'(x) = \frac{d}{dx}(ax^{-4}) - \frac{d}{dx}(bx^{-2}) + \frac{d}{dx}(\cos x)$
$f'(x) = a(-4x^{-5}) - b(-2x^{-3}) - \sin x$
$f'(x) = -\frac{4a}{x^{5}} + \frac{2b}{x^{3}} - \sin x$.

Explore More

Similar Questions

If $y = \cos (\sin {x^2}),$ then at $x = \sqrt {\frac{\pi }{2}} , \frac{dy}{dx} = $

If $y = \sin^{-1} \left( x\sqrt{1 - x} + \sqrt{x} \sqrt{1 - x^2} \right)$ and $\frac{dy}{dx} = \frac{1}{2\sqrt{x(1 - x)}} + p$,then $p =$

If $f(1)=1$ and $f^{\prime}(1)=3$,then the derivative of $f(f(f(x)))+(f(x))^2$ at $x=1$ is

$\frac{d}{dx}(x^2 e^x \sin x) = $

The value of $\frac{d}{dx}[|x - 1| + |x - 5|]$ at $x = 3$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo