Find the domain and range of the following re | vedclass

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(A) The function is defined when $9 - x^{2} \ge 0$.This implies $x^{2} \le 9$,which means $-3 \le x \le 3$.Thus,the domain of $f(x)$ is $[-3, 3]$.Sinc

Vedclass · Accepted Answer

Domain: $[-3, 3]$,Range: $[0, 3]$

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(A) The function is defined when $9 - x^{2} \ge 0$.This implies $x^{2} \le 9$,which means $-3 \le x \le 3$.Thus,the domain of $f(x)$ is $[-3, 3]$.Since $f(x) = \sqrt{9 - x^{2}}$,the minimum value occurs at $x = \pm 3$,giving $f(x) = 0$.The maximum value occurs at $x = 0$,giving $f(x) = \sqrt{9} = 3$.Therefore,the range of $f(x)$ is $[0, 3]$.

Find the domain and range of the following real function:
$f(x) = \sqrt{9 - x^{2}}$

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Find the domain and range of the following real function:$f(x) = \sqrt{9 - x^{2}}$