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(A) The intercept form of a line is given by $\frac{x}{a} + \frac{y}{b} = 1$,where $a$ and $b$ are the $x$-intercept and $y$-intercept respectively.Gi

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$2x - 3y + 6 = 0$

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(A) The intercept form of a line is given by $\frac{x}{a} + \frac{y}{b} = 1$,where $a$ and $b$ are the $x$-intercept and $y$-intercept respectively.Given $a = -3$ and $b = 2$.Substituting these values into the formula:$\frac{x}{-3} + \frac{y}{2} = 1$Multiplying the entire equation by $6$ to clear the denominators:$-2x + 3y = 6$Rearranging the terms to the standard form $Ax + By + C = 0$:$2x - 3y + 6 = 0$

Find the equation of the line,which makes intercepts $-3$ and $2$ on the $x$- and $y$-axes respectively.

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