Find the Least Common Multiple (LCM) of 220 a | vedclass

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(A) To find the $LCM$ of $220$ and $60$,we first find the prime factorization of each number:$220 = 2^2 	imes 5^1 	imes 11^1$$60 = 2^2 	imes 3^1

Vedclass · Accepted Answer

$660$

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(A) To find the $LCM$ of $220$ and $60$,we first find the prime factorization of each number:$220 = 2^2 	imes 5^1 	imes 11^1$$60 = 2^2 	imes 3^1 	imes 5^1$The $LCM$ is the product of the highest power of each prime factor present in the numbers:$LCM(220, 60) = 2^2 	imes 3^1 	imes 5^1 	imes 11^1$$LCM(220, 60) = 4 	imes 3 	imes 5 	imes 11$$LCM(220, 60) = 12 	imes 55 = 660$Therefore,the $LCM$ of $220$ and $60$ is $660$.

Find the Least Common Multiple $(LCM)$ of $220$ and $60$.

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