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(D) The required number is given by the formula: $	ext{Required Number} = (	ext{L.C.M. of } 15, 20, 36, 48) + 3$.First,we find the $L.C.M.$ of $15,

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$723$

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(D) The required number is given by the formula: $	ext{Required Number} = (	ext{L.C.M. of } 15, 20, 36, 48) + 3$.First,we find the $L.C.M.$ of $15, 20, 36$ and $48$ using the division method:$\begin{array}{c|cccc} 2 & 15, & 20, & 36, & 48 \ \hline 2 & 15, & 10, & 18, & 24 \ \hline 3 & 15, & 5, & 9, & 12 \ \hline 5 & 5, & 1, & 3, & 4 \end{array}$$	herefore L.C.M. = 2 	imes 2 	imes 3 	imes 5 	imes 1 	imes 1 	imes 3 	imes 4 = 720$.Now,add the remainder $3$ to the $L.C.M.$:$	ext{Required Number} = 720 + 3 = 723$.

Find the least number which when divided separately by $15, 20, 36$ and $48$ leaves $3$ as remainder in each case.

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