Find the mean of the distribution: Class | vedclass

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(D) To find the mean,we first calculate the class mark $(x_i)$ for each class interval using the formula: $x_i = \frac{	ext{Upper limit} + 	ext{Lowe

Vedclass · Accepted Answer

$5.5$

Vedclass · Answer

(D) To find the mean,we first calculate the class mark $(x_i)$ for each class interval using the formula: $x_i = \frac{	ext{Upper limit} + 	ext{Lower limit}}{2}$.						Class			Class mark $(x_i)$			Frequency $(f_i)$			$f_i x_i$							$1-3$			$2$			$9$			$18$							$3-5$			$4$			$22$			$88$							$5-7$			$6$			$27$			$162$							$7-10$			$8.5$			$17$			$144.5$							Total			-			$\Sigma f_i = 75$			$\Sigma f_i x_i = 412.5$			The mean $(\bar{x})$ is calculated as:$\bar{x} = \frac{\Sigma f_i x_i}{\Sigma f_i} = \frac{412.5}{75} = 5.5$.Thus,the mean of the given distribution is $5.5$.

Class	$0-30$	$30-60$	$60-90$	$90-120$	$120-150$	$150-180$
Frequency	$8$	$15$	$16$	$20$	$12$	$9$

Class	$0-100$	$100-200$	$200-300$	$300-400$	$400-500$	$500-600$	$600-700$	$700-800$	$800-900$	$900-1000$
Frequency	$2$	$5$	$x$	$12$	$17$	$20$	$y$	$9$	$7$	$4$

Find the mean of the distribution:

Class $1-3$ $3-5$ $5-7$ $7-10$

Frequency $9$ $22$ $27$ $17$

Similar Questions

Find the mean,median and mode of the following frequency distribution:

Class $0-30$ $30-60$ $60-90$ $90-120$ $120-150$ $150-180$

Frequency $8$ $15$ $16$ $20$ $12$ $9$

The median of the following frequency distribution is $525$ and the total frequency is $100$. Find the missing frequencies $x$ and $y$.

Class $0-100$ $100-200$ $200-300$ $300-400$ $400-500$ $500-600$ $600-700$ $700-800$ $800-900$ $900-1000$

Frequency $2$ $5$ $x$ $12$ $17$ $20$ $y$ $9$ $7$ $4$

In the formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$,$x_{i}$ represents ..........

The formula to find the median of a grouped data is $\ldots \ldots \ldots \ldots .$

In the usual notations,$Z - M = \ldots \ldots \ldots \quad (M - \bar{x})$

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Find the mean of the distribution: Class $1-3$ $3-5$ $5-7$ $7-10$ Frequency $9$ $22$ $27$ $17$