Find the number of orbitals and maximum elect | vedclass

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(B) The $M$-shell corresponds to the principal quantum number $n = 3$.For $n = 3$,the possible values of the azimuthal quantum number $l$ are $0, 1, 2

Vedclass · Accepted Answer

$9, 18$

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(B) The $M$-shell corresponds to the principal quantum number $n = 3$.For $n = 3$,the possible values of the azimuthal quantum number $l$ are $0, 1, 2$,which correspond to the $3s, 3p,$ and $3d$ subshells.The number of orbitals in a subshell is given by $2l + 1$.For $l = 0$ $(3s)$: $2(0) + 1 = 1$ orbital.For $l = 1$ $(3p)$: $2(1) + 1 = 3$ orbitals.For $l = 2$ $(3d)$: $2(2) + 1 = 5$ orbitals.Total number of orbitals $= 1 + 3 + 5 = 9$.Each orbital can accommodate a maximum of $2$ electrons.Therefore,the maximum number of electrons in the $M$-shell $= 9 	imes 2 = 18$.

Find the number of orbitals and maximum electrons respectively present in $M$-shell?

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