(A) We know that $180^{\circ} = \pi \text{ radians}$.Therefore,$1^{\circ} = \frac{\pi}{180} \text{ radians}$.To convert $25^{\circ}$ into radians,we m

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(A) We know that $180^{\circ} = \pi \text{ radians}$.Therefore,$1^{\circ} = \frac{\pi}{180} \text{ radians}$.To convert $25^{\circ}$ into radians,we multiply by $\frac{\pi}{180}$:$25^{\circ} = 25 \times \frac{\pi}{180} \text{ radians}$.Simplifying the fraction by dividing both numerator and denominator by $5$:$25^{\circ} = \frac{5 \pi}{36} \text{ radians}$.

Class 11 Mathematics Trigonometrical Ratios, Functions and Identities Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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Find the radian measure corresponding to the following degree measure: $25^{\circ}$

A
$\frac{5 \pi}{36}$
B
$\frac{5 \pi}{18}$
C
$\frac{5 \pi}{9}$
D
$\frac{5 \pi}{72}$

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Trigonometrical Ratios, Functions and Identities

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Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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Find the radian measure corresponding to the following degree measure: $25^{\circ}$

Similar Questions

$\cos ^2 45^{\circ}+\cos ^2 135^{\circ}+\cos ^2 225^{\circ}+\cos ^2 315^{\circ} = $

If $\cot x = -\frac{5}{12}$ and $x$ lies in the second quadrant,find the values of the other five trigonometric functions.

Convert $40^{\circ} 20^{\prime}$ into radian measure.

Which of the following equations has no solution?

Prove that $\cos \left(\frac{3 \pi}{2}+x\right) \cos (2 \pi+x)\left[\cot \left(\frac{3 \pi}{2}-x\right)+\cot (2 \pi+x)\right]=1$.

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