Find the radian measure corresponding to the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We know that $1^{\circ} = 60^{\prime}$,so $30^{\prime} = (\frac{30}{60})^{\circ} = 0.5^{\circ}$.Thus,$-47^{\circ} 30^{\prime} = -(47 + 0.5)^{\circ

Vedclass · Accepted Answer

$-\frac{19}{72} \pi$

Vedclass · Answer

(A) We know that $1^{\circ} = 60^{\prime}$,so $30^{\prime} = (\frac{30}{60})^{\circ} = 0.5^{\circ}$.Thus,$-47^{\circ} 30^{\prime} = -(47 + 0.5)^{\circ} = -47.5^{\circ} = -\frac{95}{2}^{\circ}$.Since $180^{\circ} = \pi 	ext{ radians}$,$1^{\circ} = \frac{\pi}{180} 	ext{ radians}$.Therefore,$-\frac{95}{2}^{\circ} = (-\frac{95}{2}) 	imes \frac{\pi}{180} 	ext{ radians}$.Simplifying the expression: $(-\frac{95}{360}) \pi = -\frac{19}{72} \pi 	ext{ radians}$.Hence,$-47^{\circ} 30^{\prime} = -\frac{19}{72} \pi 	ext{ radians}$.

Find the radian measure corresponding to the following degree measure: $-47^{\circ} 30^{\prime}$.

Similar Questions

Prove that: $\cot ^{2} \frac{\pi}{6} + \csc \frac{5 \pi}{6} + 3 \tan ^{2} \frac{\pi}{6} = 6$

Find the values of the other five trigonometric functions if $\sec x = \frac{13}{5}$ and $x$ lies in the fourth quadrant.

Find the degree measure of the angle subtended at the centre of a circle of radius $100 \, cm$ by an arc of length $22 \, cm$ (Use $\pi = \frac{22}{7}$).

$\frac{\sin \theta}{1-\cot \theta} + \frac{\cos \theta}{1-\tan \theta} = $

Which of the following is not correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module