Find the standard enthalpy of formation of am | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The standard enthalpy of formation $(\Delta_{f}H^0)$ is defined as the enthalpy change when $1 \ mol$ of a substance is formed from its constituen

Vedclass · Accepted Answer

$-46.0 \ kJ \ mol^{-1}$

Vedclass · Answer

(C) The standard enthalpy of formation $(\Delta_{f}H^0)$ is defined as the enthalpy change when $1 \ mol$ of a substance is formed from its constituent elements in their standard states.For the reaction: $N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}$,the enthalpy change is $\Delta_{r}H^0 = -92.0 \ kJ$ for the production of $2 \ mol$ of $NH_3$.To find the enthalpy of formation per mole of $NH_3$,we divide the reaction enthalpy by the stoichiometric coefficient of $NH_3$:$\Delta_{f}H^0(NH_3) = \frac{\Delta_{r}H^0}{2} = \frac{-92.0 \ kJ}{2} = -46.0 \ kJ \ mol^{-1}$.

Find the standard enthalpy of formation of ammonia from the following reaction:
$N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)} ; \Delta_{r}H^0 = -92.0 \ kJ$

Similar Questions

Which of the following acids will release the maximum amount of heat when completely neutralized by a strong base $NaOH$?

The bond energy (in $kcal \ mol^{-1}$) of a $C-C$ single bond is approximately:

The heat evolved per mole of $H^+$ ions during the neutralization of a strong acid and a strong base is ......

The standard enthalpy of formation of $NH_3$ is $-46.0 \, kJ/mol$. If the enthalpy of formation of $H_2$ from its atoms is $-436 \, kJ/mol$ and that of $N_2$ is $-712 \, kJ/mol$,the average bond enthalpy of $N-H$ bond in $NH_3$ is......$kJ/mol$

The values of heat of formation of $SO_2$ and $SO_3$ are $-298.2 \ kJ$ and $-395.2 \ kJ$ respectively. The heat of reaction for the following reaction will be $... \ kJ$
$SO_2 + \frac{1}{2}O_2 \to SO_3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Find the standard enthalpy of formation of ammonia from the following reaction:$N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)} ; \Delta_{r}H^0 = -92.0 \ kJ$