Find the sum:1+(-2)+(-5)+(-8)+ldots+(-236) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given series is an Arithmetic Progression $(AP)$ where the first term $a = 1$ and the common difference $d = -2 - 1 = -3$.The last term is $l

Vedclass · Accepted Answer

$-9400$

Vedclass · Answer

(B) The given series is an Arithmetic Progression $(AP)$ where the first term $a = 1$ and the common difference $d = -2 - 1 = -3$.The last term is $l = a_n = -236$.Using the formula for the $n^{th}$ term of an $AP$: $a_n = a + (n - 1)d$.$-236 = 1 + (n - 1)(-3)$$-237 = (n - 1)(-3)$$n - 1 = 79$$n = 80$.Now,the sum of $n$ terms of an $AP$ is given by $S_n = \frac{n}{2}(a + l)$.$S_{80} = \frac{80}{2}(1 + (-236))$$S_{80} = 40 	imes (-235)$$S_{80} = -9400$.

Find the sum:
$1+(-2)+(-5)+(-8)+\ldots+(-236)$

Similar Questions

For the finite $A.P.$ $5, 9, 13, \ldots, 101$,find the $9^{th}$ term from the end.

The sum of the first five terms of an $AP$ and the sum of the first seven terms of the same $AP$ is $167$. If the sum of the first ten terms of this $AP$ is $235$,find the sum of its first twenty terms.

For the $A.P.$ $\frac{3}{2}, \frac{7}{2}, \frac{11}{2}, \frac{15}{2}, \ldots,$ the common difference is

The formula to find the $n^{th}$ term of an $A.P.$ is $\ldots \ldots \ldots \ldots .$

Which of the following sequences is an $A.P.$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Find the sum:$1+(-2)+(-5)+(-8)+\ldots+(-236)$