Find the value of $p(x) = 2x^3 + x^2 - x - 1$ at $x = 0$ and $x = -2$.
(N/A) Given polynomial: $p(x) = 2x^3 + x^2 - x - 1$
Step $1$: Find the value at $x = 0$.
$p(0) = 2(0)^3 + (0)^2 - (0) - 1$
$p(0) = 0 + 0 - 0 - 1$
$p(0) = -1$
Step $2$: Find the value at $x = -2$.
$p(-2) = 2(-2)^3 + (-2)^2 - (-2) - 1$
$p(-2) = 2(-8) + 4 + 2 - 1$
$p(-2) = -16 + 4 + 2 - 1$
$p(-2) = -11$
Thus,the values are $p(0) = -1$ and $p(-2) = -11$.
Step $1$: Find the value at $x = 0$.
$p(0) = 2(0)^3 + (0)^2 - (0) - 1$
$p(0) = 0 + 0 - 0 - 1$
$p(0) = -1$
Step $2$: Find the value at $x = -2$.
$p(-2) = 2(-2)^3 + (-2)^2 - (-2) - 1$
$p(-2) = 2(-8) + 4 + 2 - 1$
$p(-2) = -16 + 4 + 2 - 1$
$p(-2) = -11$
Thus,the values are $p(0) = -1$ and $p(-2) = -11$.
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