Find the values of x and y in the following r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) By the property of a rectangle,opposite sides are equal.For lengths: $x + 3y = 13$  --- $(i)$For breadths: $3x + y = 7$  --- $(ii)$To solve this p

Vedclass · Accepted Answer

$1, 4$

Vedclass · Answer

(B) By the property of a rectangle,opposite sides are equal.For lengths: $x + 3y = 13$  --- $(i)$For breadths: $3x + y = 7$  --- $(ii)$To solve this pair of linear equations,multiply equation $(ii)$ by $3$:$9x + 3y = 21$  --- $(iii)$Now,subtract equation $(i)$ from equation $(iii)$:$(9x + 3y) - (x + 3y) = 21 - 13$$8x = 8$$x = 1$Substitute $x = 1$ into equation $(i)$:$1 + 3y = 13$$3y = 12$$y = 4$Thus,the required values are $x = 1$ and $y = 4$.

Find the values of $x$ and $y$ in the following rectangle.

Similar Questions

For the pair of equations $\frac{2}{x} + \frac{3}{y} = 3$ and $\frac{3}{x} + \frac{2}{y} = 7$,find the value of $\frac{3}{x} + \frac{3}{y}$.

Solve the following pair of linear equations in two variables graphically: $2x + 3y = 12$ and $2x + 3y = 6$.

The sum of a two-digit number and the number obtained by interchanging the digits is always divisible by $\ldots \ldots \ldots \ldots$

Solve the following pair of linear equations by the method of substitution: $3x + y + 1 = 0$ and $2x - 3y + 8 = 0$.

The cost of $5$ pants and $8$ shirts is ₹ $3100$. If the cost of a pant is ₹ $x$ and a shirt is ₹ $y$,then the linear equation in two variables is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module