Find the velocity of block $B$ at the instant shown in the figure (in $m/s$).

If block $A$ is moving with an acceleration of $5\,m/s^2$,the acceleration of $B$ with respect to the ground is:

In the pulley system shown in the figure, the mass of $A$ is half of that of $\text{rod } B$. The rod length is $500 \text{ cm}$. The mass of pulleys and the threads may be neglected. The mass $A$ is set at the same level as the lower end of the rod and then released. After releasing the mass $A$, it would reach the top end of the rod $B$ in time (Assume $g=10 \text{ m/s}^2$): (in $\text{ s}$)

For the given figure,find the speed of block $A$ when $\theta = 60^\circ$. The ring moves horizontally with a constant speed of $4 \, m/s$.

$A$ block $Q$ of mass $M$ is placed on a horizontal frictionless surface $AB$ and a body $P$ of mass $m$ is released on its frictionless slope. As $P$ slides by a length $L$ on this slope of inclination $\theta$,the block $Q$ would slide by a distance:

$A$ rod of length $L$ leans against a smooth vertical wall while its other end is on a smooth floor. The end that leans against the wall moves uniformly vertically downward. Select the correct alternative.