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(C) In a body-centered cubic $(BCC)$ unit cell with edge length $a$:$1$. The first nearest neighbour distance is the distance between the corner atom

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$\frac{\sqrt{3} \ a}{2}, a, \sqrt{2} \ a$

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(C) In a body-centered cubic $(BCC)$ unit cell with edge length $a$:$1$. The first nearest neighbour distance is the distance between the corner atom and the body-center atom,which is $\frac{\sqrt{3} \ a}{2}$.$2$. The second nearest neighbour distance is the distance between two corner atoms along the edge,which is $a$.$3$. The third nearest neighbour distance is the distance between two corner atoms along the face diagonal,which is $\sqrt{2} \ a$.

The first three nearest neighbour distances for a body-centered cubic $(BCC)$ lattice are respectively:

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