Five capacitors,each of capacity $C$,are connected as shown in the figure. The resultant capacity between $A$ and $B$ is $14 \mu F$. The capacity of each capacitor is (in $\mu F$)

In the figure,three capacitors each of capacitance $6\,pF$ are connected in series. The total capacitance of the combination will be

Three capacitors each of $6\,\mu F$ are available. The minimum and maximum capacitances which may be obtained are

Three condensers of capacities $C_1$,$C_2$,and $C_3$ are connected in series with a source of e.m.f. $V$. The potentials across the three condensers are in the ratio:

Two capacitors of capacities $2 \mu F$ and $4 \mu F$ are connected in parallel. $A$ third capacitor of $6 \mu F$ capacity is connected in series with this combination. $A$ battery of $12 \text{ V}$ is connected across this combination. The charge on the $2 \mu F$ capacitor is: (in $\mu C$)

When three capacitors of equal capacities are connected in parallel and one of the same capacitor is connected in series with this combination,the resultant capacity is $3.75 \mu F$. The capacity of each capacitor is: (in $\mu F$)