Five cells each of emf $E$ and internal resistance $r$ are connected in series. Due to oversight,one cell is connected wrongly. The equivalent internal resistance of the combination is ........... $r$.

The internal resistance of a cell depends on

There are a large number of cells available,each marked $(6 \,V, 0.5 \,\Omega)$,to be used to supply current to a device of resistance $0.75 \,\Omega$,requiring $24 \,A$ current. How should the cells be arranged so that power is transmitted to the load using the minimum number of cells?

The internal resistance of a primary cell is $4\,\Omega$. It generates a current of $0.2\,A$ in an external resistance of $21\,\Omega$. The rate at which chemical energy is consumed in providing the current is .............. $J/s$.

To draw maximum current from a combination of cells,how should the cells be grouped?

The internal resistance of a cell of emf $4 \text{ V}$ is $0.1 \ \Omega$. It is connected to an external resistance of $3.9 \ \Omega$. The terminal voltage across the cell will be . . . . . . . (in $\text{ V}$)