Five men A, B, C, D and E read a newspaper. T | vedclass

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(B) $1$. Let the order of readers be $1, 2, 3, 4, 5$.$2$. There are two readers between $B$ and $A$. This means the possible positions for $(B, A)$ ar

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$C$

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(B) $1$. Let the order of readers be $1, 2, 3, 4, 5$.$2$. There are two readers between $B$ and $A$. This means the possible positions for $(B, A)$ are $(1, 4)$ or $(2, 5)$ or $(4, 1)$ or $(5, 2)$.$3$. The one who reads first gives it to $C$,so $C$ is at position $2$.$4$. The one who reads last took it from $A$,so $A$ is at position $4$.$5$. If $A$ is at $4$,then $B$ must be at $1$ (since there are two readers between them).$6$. $E$ is not first or last,so $E$ must be at position $3$.$7$. The remaining person $D$ must be at position $5$.$8$. The order is $B(1) 	o C(2) 	o E(3) 	o A(4) 	o D(5)$.$9$. Since $B$ is the first reader and he passes it to $C$,$B$ passed the newspaper to $C$.

Five men $A, B, C, D$ and $E$ read a newspaper. The one who reads first gives it to $C$. The one who reads last had taken it from $A$. $E$ was not the first or the last to read. There were two readers between $B$ and $A$. To whom did $B$ pass the newspaper?

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