Fluoride ions make the enamel of teeth much h | vedclass

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Question

(B) Teeth enamel contains hydroxyapatite,which is $[3 Ca_3(PO_4)_2 \cdot Ca(OH)_2]$.When it reacts with fluoride ions $(F^-)$,it is converted into flu

Vedclass · Accepted Answer

$[3 Ca_3(PO_4)_2 \cdot Ca(OH)_2]$

Vedclass · Answer

(B) Teeth enamel contains hydroxyapatite,which is $[3 Ca_3(PO_4)_2 \cdot Ca(OH)_2]$.When it reacts with fluoride ions $(F^-)$,it is converted into fluorapatite,which is $[3 Ca_3(PO_4)_2 \cdot CaF_2]$.This compound is much harder and more resistant to tooth decay.The reaction is:$[3 Ca_3(PO_4)_2 \cdot Ca(OH)_2] + 2 F^- \rightarrow [3 Ca_3(PO_4)_2 \cdot CaF_2] + 2 OH^-$

Fluoride ions make the enamel of teeth much harder by converting which of the following substances/compounds?

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